go issue31573 源码

  • 2022-07-15
  • 浏览 (810)

golang issue31573 代码

文件路径:/test/fixedbugs/issue31573.go

// errorcheck -0 -m

// Copyright 2019 The Go Authors. All rights reserved.
// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.

package p

func f(...*int) {} // ERROR "can inline f$"

func g() {
	defer f()
	defer f(new(int))           // ERROR "... argument does not escape$" "new\(int\) does not escape$"
	defer f(new(int), new(int)) // ERROR "... argument does not escape$" "new\(int\) does not escape$"

	defer f(nil...)
	defer f([]*int{}...)                   // ERROR "\[\]\*int{} does not escape$"
	defer f([]*int{new(int)}...)           // ERROR "\[\]\*int{...} does not escape$" "new\(int\) does not escape$"
	defer f([]*int{new(int), new(int)}...) // ERROR "\[\]\*int{...} does not escape$" "new\(int\) does not escape$"

	go f()
	go f(new(int))           // ERROR "... argument does not escape$" "new\(int\) escapes to heap$"
	go f(new(int), new(int)) // ERROR "... argument does not escape$" "new\(int\) escapes to heap$"

	go f(nil...)
	go f([]*int{}...)                   // ERROR "\[\]\*int{} does not escape$"
	go f([]*int{new(int)}...)           // ERROR "\[\]\*int{...} does not escape$" "new\(int\) escapes to heap$"
	go f([]*int{new(int), new(int)}...) // ERROR "\[\]\*int{...} does not escape$" "new\(int\) escapes to heap$"

	for {
		defer f()
		defer f(new(int))           // ERROR "... argument does not escape$" "new\(int\) escapes to heap$"
		defer f(new(int), new(int)) // ERROR "... argument does not escape$" "new\(int\) escapes to heap$"

		defer f(nil...)
		defer f([]*int{}...)                   // ERROR "\[\]\*int{} does not escape$"
		defer f([]*int{new(int)}...)           // ERROR "\[\]\*int{...} does not escape$" "new\(int\) escapes to heap$"
		defer f([]*int{new(int), new(int)}...) // ERROR "\[\]\*int{...} does not escape$" "new\(int\) escapes to heap$"

		go f()
		go f(new(int))           // ERROR "... argument does not escape$" "new\(int\) escapes to heap$"
		go f(new(int), new(int)) // ERROR "... argument does not escape$" "new\(int\) escapes to heap$"

		go f(nil...)
		go f([]*int{}...)                   // ERROR "\[\]\*int{} does not escape$"
		go f([]*int{new(int)}...)           // ERROR "\[\]\*int{...} does not escape$" "new\(int\) escapes to heap$"
		go f([]*int{new(int), new(int)}...) // ERROR "\[\]\*int{...} does not escape$" "new\(int\) escapes to heap$"
	}
}

相关信息

go 源码目录

相关文章

go bug000 源码

go bug002 源码

go bug003 源码

go bug004 源码

go bug005 源码

go bug006 源码

go bug007 源码

go bug008 源码

go bug009 源码

go bug010 源码

0  赞