greenplumn d2s 源码
greenplumn d2s 代码
文件路径：/src/common/d2s.c
/*---------------------------------------------------------------------------
*
* Ryu floating-point output for double precision.
*
* Portions Copyright (c) 2018-2019, PostgreSQL Global Development Group
*
* IDENTIFICATION
* src/common/d2s.c
*
* This is a modification of code taken from github.com/ulfjack/ryu under the
* terms of the Boost license (not the Apache license). The original copyright
* notice follows:
*
* Copyright 2018 Ulf Adams
*
* The contents of this file may be used under the terms of the Apache
* License, Version 2.0.
*
* (See accompanying file LICENSE-Apache or copy at
* http://www.apache.org/licenses/LICENSE-2.0)
*
* Alternatively, the contents of this file may be used under the terms of the
* Boost Software License, Version 1.0.
*
* (See accompanying file LICENSE-Boost or copy at
* https://www.boost.org/LICENSE_1_0.txt)
*
* Unless required by applicable law or agreed to in writing, this software is
* distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
* KIND, either express or implied.
*
*---------------------------------------------------------------------------
*/
/*
* Runtime compiler options:
*
* -DRYU_ONLY_64_BIT_OPS Avoid using uint128 or 64-bit intrinsics. Slower,
* depending on your compiler.
*/
#ifndef FRONTEND
#include "postgres.h"
#else
#include "postgres_fe.h"
#endif
#include "common/shortest_dec.h"
/*
* For consistency, we use 128-bit types if and only if the rest of PG also
* does, even though we could use them here without worrying about the
* alignment concerns that apply elsewhere.
*/
#if !defined(HAVE_INT128) && defined(_MSC_VER) \
&& !defined(RYU_ONLY_64_BIT_OPS) && defined(_M_X64)
#define HAS_64_BIT_INTRINSICS
#endif
#include "ryu_common.h"
#include "digit_table.h"
#include "d2s_full_table.h"
#include "d2s_intrinsics.h"
#define DOUBLE_MANTISSA_BITS 52
#define DOUBLE_EXPONENT_BITS 11
#define DOUBLE_BIAS 1023
#define DOUBLE_POW5_INV_BITCOUNT 122
#define DOUBLE_POW5_BITCOUNT 121
static inline uint32
pow5Factor(uint64 value)
{
uint32 count = 0;
for (;;)
{
Assert(value != 0);
const uint64 q = div5(value);
const uint32 r = (uint32) (value - 5 * q);
if (r != 0)
break;
value = q;
++count;
}
return count;
}
/* Returns true if value is divisible by 5^p. */
static inline bool
multipleOfPowerOf5(const uint64 value, const uint32 p)
{
/*
* I tried a case distinction on p, but there was no performance
* difference.
*/
return pow5Factor(value) >= p;
}
/* Returns true if value is divisible by 2^p. */
static inline bool
multipleOfPowerOf2(const uint64 value, const uint32 p)
{
/* return __builtin_ctzll(value) >= p; */
return (value & ((UINT64CONST(1) << p) - 1)) == 0;
}
/*
* We need a 64x128-bit multiplication and a subsequent 128-bit shift.
*
* Multiplication:
*
* The 64-bit factor is variable and passed in, the 128-bit factor comes
* from a lookup table. We know that the 64-bit factor only has 55
* significant bits (i.e., the 9 topmost bits are zeros). The 128-bit
* factor only has 124 significant bits (i.e., the 4 topmost bits are
* zeros).
*
* Shift:
*
* In principle, the multiplication result requires 55 + 124 = 179 bits to
* represent. However, we then shift this value to the right by j, which is
* at least j >= 115, so the result is guaranteed to fit into 179 - 115 =
* 64 bits. This means that we only need the topmost 64 significant bits of
* the 64x128-bit multiplication.
*
* There are several ways to do this:
*
* 1. Best case: the compiler exposes a 128-bit type.
* We perform two 64x64-bit multiplications, add the higher 64 bits of the
* lower result to the higher result, and shift by j - 64 bits.
*
* We explicitly cast from 64-bit to 128-bit, so the compiler can tell
* that these are only 64-bit inputs, and can map these to the best
* possible sequence of assembly instructions. x86-64 machines happen to
* have matching assembly instructions for 64x64-bit multiplications and
* 128-bit shifts.
*
* 2. Second best case: the compiler exposes intrinsics for the x86-64
* assembly instructions mentioned in 1.
*
* 3. We only have 64x64 bit instructions that return the lower 64 bits of
* the result, i.e., we have to use plain C.
*
* Our inputs are less than the full width, so we have three options:
* a. Ignore this fact and just implement the intrinsics manually.
* b. Split both into 31-bit pieces, which guarantees no internal
* overflow, but requires extra work upfront (unless we change the
* lookup table).
* c. Split only the first factor into 31-bit pieces, which also
* guarantees no internal overflow, but requires extra work since the
* intermediate results are not perfectly aligned.
*/
#if defined(HAVE_INT128)
/* Best case: use 128-bit type. */
static inline uint64
mulShift(const uint64 m, const uint64 *const mul, const int32 j)
{
const uint128 b0 = ((uint128) m) * mul[0];
const uint128 b2 = ((uint128) m) * mul[1];
return (uint64) (((b0 >> 64) + b2) >> (j - 64));
}
static inline uint64
mulShiftAll(const uint64 m, const uint64 *const mul, const int32 j,
uint64 *const vp, uint64 *const vm, const uint32 mmShift)
{
*vp = mulShift(4 * m + 2, mul, j);
*vm = mulShift(4 * m - 1 - mmShift, mul, j);
return mulShift(4 * m, mul, j);
}
#elif defined(HAS_64_BIT_INTRINSICS)
static inline uint64
mulShift(const uint64 m, const uint64 *const mul, const int32 j)
{
/* m is maximum 55 bits */
uint64 high1;
/* 128 */
const uint64 low1 = umul128(m, mul[1], &high1);
/* 64 */
uint64 high0;
uint64 sum;
/* 64 */
umul128(m, mul[0], &high0);
/* 0 */
sum = high0 + low1;
if (sum < high0)
{
++high1;
/* overflow into high1 */
}
return shiftright128(sum, high1, j - 64);
}
static inline uint64
mulShiftAll(const uint64 m, const uint64 *const mul, const int32 j,
uint64 *const vp, uint64 *const vm, const uint32 mmShift)
{
*vp = mulShift(4 * m + 2, mul, j);
*vm = mulShift(4 * m - 1 - mmShift, mul, j);
return mulShift(4 * m, mul, j);
}
#else /* // !defined(HAVE_INT128) &&
* !defined(HAS_64_BIT_INTRINSICS) */
static inline uint64
mulShiftAll(uint64 m, const uint64 *const mul, const int32 j,
uint64 *const vp, uint64 *const vm, const uint32 mmShift)
{
m <<= 1; /* m is maximum 55 bits */
uint64 tmp;
const uint64 lo = umul128(m, mul[0], &tmp);
uint64 hi;
const uint64 mid = tmp + umul128(m, mul[1], &hi);
hi += mid < tmp; /* overflow into hi */
const uint64 lo2 = lo + mul[0];
const uint64 mid2 = mid + mul[1] + (lo2 < lo);
const uint64 hi2 = hi + (mid2 < mid);
*vp = shiftright128(mid2, hi2, j - 64 - 1);
if (mmShift == 1)
{
const uint64 lo3 = lo - mul[0];
const uint64 mid3 = mid - mul[1] - (lo3 > lo);
const uint64 hi3 = hi - (mid3 > mid);
*vm = shiftright128(mid3, hi3, j - 64 - 1);
}
else
{
const uint64 lo3 = lo + lo;
const uint64 mid3 = mid + mid + (lo3 < lo);
const uint64 hi3 = hi + hi + (mid3 < mid);
const uint64 lo4 = lo3 - mul[0];
const uint64 mid4 = mid3 - mul[1] - (lo4 > lo3);
const uint64 hi4 = hi3 - (mid4 > mid3);
*vm = shiftright128(mid4, hi4, j - 64);
}
return shiftright128(mid, hi, j - 64 - 1);
}
#endif /* // HAS_64_BIT_INTRINSICS */
static inline uint32
decimalLength(const uint64 v)
{
/* This is slightly faster than a loop. */
/* The average output length is 16.38 digits, so we check high-to-low. */
/* Function precondition: v is not an 18, 19, or 20-digit number. */
/* (17 digits are sufficient for round-tripping.) */
Assert(v < 100000000000000000L);
if (v >= 10000000000000000L)
{
return 17;
}
if (v >= 1000000000000000L)
{
return 16;
}
if (v >= 100000000000000L)
{
return 15;
}
if (v >= 10000000000000L)
{
return 14;
}
if (v >= 1000000000000L)
{
return 13;
}
if (v >= 100000000000L)
{
return 12;
}
if (v >= 10000000000L)
{
return 11;
}
if (v >= 1000000000L)
{
return 10;
}
if (v >= 100000000L)
{
return 9;
}
if (v >= 10000000L)
{
return 8;
}
if (v >= 1000000L)
{
return 7;
}
if (v >= 100000L)
{
return 6;
}
if (v >= 10000L)
{
return 5;
}
if (v >= 1000L)
{
return 4;
}
if (v >= 100L)
{
return 3;
}
if (v >= 10L)
{
return 2;
}
return 1;
}
/* A floating decimal representing m * 10^e. */
typedef struct floating_decimal_64
{
uint64 mantissa;
int32 exponent;
} floating_decimal_64;
static inline floating_decimal_64
d2d(const uint64 ieeeMantissa, const uint32 ieeeExponent)
{
int32 e2;
uint64 m2;
if (ieeeExponent == 0)
{
/* We subtract 2 so that the bounds computation has 2 additional bits. */
e2 = 1 - DOUBLE_BIAS - DOUBLE_MANTISSA_BITS - 2;
m2 = ieeeMantissa;
}
else
{
e2 = ieeeExponent - DOUBLE_BIAS - DOUBLE_MANTISSA_BITS - 2;
m2 = (UINT64CONST(1) << DOUBLE_MANTISSA_BITS) | ieeeMantissa;
}
#if STRICTLY_SHORTEST
const bool even = (m2 & 1) == 0;
const bool acceptBounds = even;
#else
const bool acceptBounds = false;
#endif
/* Step 2: Determine the interval of legal decimal representations. */
const uint64 mv = 4 * m2;
/* Implicit bool -> int conversion. True is 1, false is 0. */
const uint32 mmShift = ieeeMantissa != 0 || ieeeExponent <= 1;
/* We would compute mp and mm like this: */
/* uint64 mp = 4 * m2 + 2; */
/* uint64 mm = mv - 1 - mmShift; */
/* Step 3: Convert to a decimal power base using 128-bit arithmetic. */
uint64 vr,
vp,
vm;
int32 e10;
bool vmIsTrailingZeros = false;
bool vrIsTrailingZeros = false;
if (e2 >= 0)
{
/*
* I tried special-casing q == 0, but there was no effect on
* performance.
*
* This expr is slightly faster than max(0, log10Pow2(e2) - 1).
*/
const uint32 q = log10Pow2(e2) - (e2 > 3);
const int32 k = DOUBLE_POW5_INV_BITCOUNT + pow5bits(q) - 1;
const int32 i = -e2 + q + k;
e10 = q;
vr = mulShiftAll(m2, DOUBLE_POW5_INV_SPLIT[q], i, &vp, &vm, mmShift);
if (q <= 21)
{
/*
* This should use q <= 22, but I think 21 is also safe. Smaller
* values may still be safe, but it's more difficult to reason
* about them.
*
* Only one of mp, mv, and mm can be a multiple of 5, if any.
*/
const uint32 mvMod5 = (uint32) (mv - 5 * div5(mv));
if (mvMod5 == 0)
{
vrIsTrailingZeros = multipleOfPowerOf5(mv, q);
}
else if (acceptBounds)
{
/*----
* Same as min(e2 + (~mm & 1), pow5Factor(mm)) >= q
* <=> e2 + (~mm & 1) >= q && pow5Factor(mm) >= q
* <=> true && pow5Factor(mm) >= q, since e2 >= q.
*----
*/
vmIsTrailingZeros = multipleOfPowerOf5(mv - 1 - mmShift, q);
}
else
{
/* Same as min(e2 + 1, pow5Factor(mp)) >= q. */
vp -= multipleOfPowerOf5(mv + 2, q);
}
}
}
else
{
/*
* This expression is slightly faster than max(0, log10Pow5(-e2) - 1).
*/
const uint32 q = log10Pow5(-e2) - (-e2 > 1);
const int32 i = -e2 - q;
const int32 k = pow5bits(i) - DOUBLE_POW5_BITCOUNT;
const int32 j = q - k;
e10 = q + e2;
vr = mulShiftAll(m2, DOUBLE_POW5_SPLIT[i], j, &vp, &vm, mmShift);
if (q <= 1)
{
/*
* {vr,vp,vm} is trailing zeros if {mv,mp,mm} has at least q
* trailing 0 bits.
*/
/* mv = 4 * m2, so it always has at least two trailing 0 bits. */
vrIsTrailingZeros = true;
if (acceptBounds)
{
/*
* mm = mv - 1 - mmShift, so it has 1 trailing 0 bit iff
* mmShift == 1.
*/
vmIsTrailingZeros = mmShift == 1;
}
else
{
/*
* mp = mv + 2, so it always has at least one trailing 0 bit.
*/
--vp;
}
}
else if (q < 63)
{
/* TODO(ulfjack):Use a tighter bound here. */
/*
* We need to compute min(ntz(mv), pow5Factor(mv) - e2) >= q - 1
*/
/* <=> ntz(mv) >= q - 1 && pow5Factor(mv) - e2 >= q - 1 */
/* <=> ntz(mv) >= q - 1 (e2 is negative and -e2 >= q) */
/* <=> (mv & ((1 << (q - 1)) - 1)) == 0 */
/*
* We also need to make sure that the left shift does not
* overflow.
*/
vrIsTrailingZeros = multipleOfPowerOf2(mv, q - 1);
}
}
/*
* Step 4: Find the shortest decimal representation in the interval of
* legal representations.
*/
uint32 removed = 0;
uint8 lastRemovedDigit = 0;
uint64 output;
/* On average, we remove ~2 digits. */
if (vmIsTrailingZeros || vrIsTrailingZeros)
{
/* General case, which happens rarely (~0.7%). */
for (;;)
{
const uint64 vpDiv10 = div10(vp);
const uint64 vmDiv10 = div10(vm);
if (vpDiv10 <= vmDiv10)
break;
const uint32 vmMod10 = (uint32) (vm - 10 * vmDiv10);
const uint64 vrDiv10 = div10(vr);
const uint32 vrMod10 = (uint32) (vr - 10 * vrDiv10);
vmIsTrailingZeros &= vmMod10 == 0;
vrIsTrailingZeros &= lastRemovedDigit == 0;
lastRemovedDigit = (uint8) vrMod10;
vr = vrDiv10;
vp = vpDiv10;
vm = vmDiv10;
++removed;
}
if (vmIsTrailingZeros)
{
for (;;)
{
const uint64 vmDiv10 = div10(vm);
const uint32 vmMod10 = (uint32) (vm - 10 * vmDiv10);
if (vmMod10 != 0)
break;
const uint64 vpDiv10 = div10(vp);
const uint64 vrDiv10 = div10(vr);
const uint32 vrMod10 = (uint32) (vr - 10 * vrDiv10);
vrIsTrailingZeros &= lastRemovedDigit == 0;
lastRemovedDigit = (uint8) vrMod10;
vr = vrDiv10;
vp = vpDiv10;
vm = vmDiv10;
++removed;
}
}
if (vrIsTrailingZeros && lastRemovedDigit == 5 && vr % 2 == 0)
{
/* Round even if the exact number is .....50..0. */
lastRemovedDigit = 4;
}
/*
* We need to take vr + 1 if vr is outside bounds or we need to round
* up.
*/
output = vr + ((vr == vm && (!acceptBounds || !vmIsTrailingZeros)) || lastRemovedDigit >= 5);
}
else
{
/*
* Specialized for the common case (~99.3%). Percentages below are
* relative to this.
*/
bool roundUp = false;
const uint64 vpDiv100 = div100(vp);
const uint64 vmDiv100 = div100(vm);
if (vpDiv100 > vmDiv100)
{
/* Optimization:remove two digits at a time(~86.2 %). */
const uint64 vrDiv100 = div100(vr);
const uint32 vrMod100 = (uint32) (vr - 100 * vrDiv100);
roundUp = vrMod100 >= 50;
vr = vrDiv100;
vp = vpDiv100;
vm = vmDiv100;
removed += 2;
}
/*----
* Loop iterations below (approximately), without optimization
* above:
*
* 0: 0.03%, 1: 13.8%, 2: 70.6%, 3: 14.0%, 4: 1.40%, 5: 0.14%,
* 6+: 0.02%
*
* Loop iterations below (approximately), with optimization
* above:
*
* 0: 70.6%, 1: 27.8%, 2: 1.40%, 3: 0.14%, 4+: 0.02%
*----
*/
for (;;)
{
const uint64 vpDiv10 = div10(vp);
const uint64 vmDiv10 = div10(vm);
if (vpDiv10 <= vmDiv10)
break;
const uint64 vrDiv10 = div10(vr);
const uint32 vrMod10 = (uint32) (vr - 10 * vrDiv10);
roundUp = vrMod10 >= 5;
vr = vrDiv10;
vp = vpDiv10;
vm = vmDiv10;
++removed;
}
/*
* We need to take vr + 1 if vr is outside bounds or we need to round
* up.
*/
output = vr + (vr == vm || roundUp);
}
const int32 exp = e10 + removed;
floating_decimal_64 fd;
fd.exponent = exp;
fd.mantissa = output;
return fd;
}
static inline int
to_chars_df(const floating_decimal_64 v, const uint32 olength, char *const result)
{
/* Step 5: Print the decimal representation. */
int index = 0;
uint64 output = v.mantissa;
int32 exp = v.exponent;
/*----
* On entry, mantissa * 10^exp is the result to be output.
* Caller has already done the - sign if needed.
*
* We want to insert the point somewhere depending on the output length
* and exponent, which might mean adding zeros:
*
* exp | format
* 1+ | ddddddddd000000
* 0 | ddddddddd
* -1 .. -len+1 | dddddddd.d to d.ddddddddd
* -len ... | 0.ddddddddd to 0.000dddddd
*/
uint32 i = 0;
int32 nexp = exp + olength;
if (nexp <= 0)
{
/* -nexp is number of 0s to add after '.' */
Assert(nexp >= -3);
/* 0.000ddddd */
index = 2 - nexp;
/* won't need more than this many 0s */
memcpy(result, "0.000000", 8);
}
else if (exp < 0)
{
/*
* dddd.dddd; leave space at the start and move the '.' in after
*/
index = 1;
}
else
{
/*
* We can save some code later by pre-filling with zeros. We know that
* there can be no more than 16 output digits in this form, otherwise
* we would not choose fixed-point output.
*/
Assert(exp < 16 && exp + olength <= 16);
memset(result, '0', 16);
}
/*
* We prefer 32-bit operations, even on 64-bit platforms. We have at most
* 17 digits, and uint32 can store 9 digits. If output doesn't fit into
* uint32, we cut off 8 digits, so the rest will fit into uint32.
*/
if ((output >> 32) != 0)
{
/* Expensive 64-bit division. */
const uint64 q = div1e8(output);
uint32 output2 = (uint32) (output - 100000000 * q);
const uint32 c = output2 % 10000;
output = q;
output2 /= 10000;
const uint32 d = output2 % 10000;
const uint32 c0 = (c % 100) << 1;
const uint32 c1 = (c / 100) << 1;
const uint32 d0 = (d % 100) << 1;
const uint32 d1 = (d / 100) << 1;
memcpy(result + index + olength - i - 2, DIGIT_TABLE + c0, 2);
memcpy(result + index + olength - i - 4, DIGIT_TABLE + c1, 2);
memcpy(result + index + olength - i - 6, DIGIT_TABLE + d0, 2);
memcpy(result + index + olength - i - 8, DIGIT_TABLE + d1, 2);
i += 8;
}
uint32 output2 = (uint32) output;
while (output2 >= 10000)
{
const uint32 c = output2 - 10000 * (output2 / 10000);
const uint32 c0 = (c % 100) << 1;
const uint32 c1 = (c / 100) << 1;
output2 /= 10000;
memcpy(result + index + olength - i - 2, DIGIT_TABLE + c0, 2);
memcpy(result + index + olength - i - 4, DIGIT_TABLE + c1, 2);
i += 4;
}
if (output2 >= 100)
{
const uint32 c = (output2 % 100) << 1;
output2 /= 100;
memcpy(result + index + olength - i - 2, DIGIT_TABLE + c, 2);
i += 2;
}
if (output2 >= 10)
{
const uint32 c = output2 << 1;
memcpy(result + index + olength - i - 2, DIGIT_TABLE + c, 2);
}
else
{
result[index] = (char) ('0' + output2);
}
if (index == 1)
{
/*
* nexp is 1..15 here, representing the number of digits before the
* point. A value of 16 is not possible because we switch to
* scientific notation when the display exponent reaches 15.
*/
Assert(nexp < 16);
/* gcc only seems to want to optimize memmove for small 2^n */
if (nexp & 8)
{
memmove(result + index - 1, result + index, 8);
index += 8;
}
if (nexp & 4)
{
memmove(result + index - 1, result + index, 4);
index += 4;
}
if (nexp & 2)
{
memmove(result + index - 1, result + index, 2);
index += 2;
}
if (nexp & 1)
{
result[index - 1] = result[index];
}
result[nexp] = '.';
index = olength + 1;
}
else if (exp >= 0)
{
/* we supplied the trailing zeros earlier, now just set the length. */
index = olength + exp;
}
else
{
index = olength + (2 - nexp);
}
return index;
}
static inline int
to_chars(floating_decimal_64 v, const bool sign, char *const result)
{
/* Step 5: Print the decimal representation. */
int index = 0;
uint64 output = v.mantissa;
uint32 olength = decimalLength(output);
int32 exp = v.exponent + olength - 1;
if (sign)
{
result[index++] = '-';
}
/*
* The thresholds for fixed-point output are chosen to match printf
* defaults. Beware that both the code of to_chars_df and the value of
* DOUBLE_SHORTEST_DECIMAL_LEN are sensitive to these thresholds.
*/
if (exp >= -4 && exp < 15)
return to_chars_df(v, olength, result + index) + sign;
/*
* If v.exponent is exactly 0, we might have reached here via the small
* integer fast path, in which case v.mantissa might contain trailing
* (decimal) zeros. For scientific notation we need to move these zeros
* into the exponent. (For fixed point this doesn't matter, which is why
* we do this here rather than above.)
*
* Since we already calculated the display exponent (exp) above based on
* the old decimal length, that value does not change here. Instead, we
* just reduce the display length for each digit removed.
*
* If we didn't get here via the fast path, the raw exponent will not
* usually be 0, and there will be no trailing zeros, so we pay no more
* than one div10/multiply extra cost. We claw back half of that by
* checking for divisibility by 2 before dividing by 10.
*/
if (v.exponent == 0)
{
while ((output & 1) == 0)
{
const uint64 q = div10(output);
const uint32 r = (uint32) (output - 10 * q);
if (r != 0)
break;
output = q;
--olength;
}
}
/*----
* Print the decimal digits.
*
* The following code is equivalent to:
*
* for (uint32 i = 0; i < olength - 1; ++i) {
* const uint32 c = output % 10; output /= 10;
* result[index + olength - i] = (char) ('0' + c);
* }
* result[index] = '0' + output % 10;
*----
*/
uint32 i = 0;
/*
* We prefer 32-bit operations, even on 64-bit platforms. We have at most
* 17 digits, and uint32 can store 9 digits. If output doesn't fit into
* uint32, we cut off 8 digits, so the rest will fit into uint32.
*/
if ((output >> 32) != 0)
{
/* Expensive 64-bit division. */
const uint64 q = div1e8(output);
uint32 output2 = (uint32) (output - 100000000 * q);
output = q;
const uint32 c = output2 % 10000;
output2 /= 10000;
const uint32 d = output2 % 10000;
const uint32 c0 = (c % 100) << 1;
const uint32 c1 = (c / 100) << 1;
const uint32 d0 = (d % 100) << 1;
const uint32 d1 = (d / 100) << 1;
memcpy(result + index + olength - i - 1, DIGIT_TABLE + c0, 2);
memcpy(result + index + olength - i - 3, DIGIT_TABLE + c1, 2);
memcpy(result + index + olength - i - 5, DIGIT_TABLE + d0, 2);
memcpy(result + index + olength - i - 7, DIGIT_TABLE + d1, 2);
i += 8;
}
uint32 output2 = (uint32) output;
while (output2 >= 10000)
{
const uint32 c = output2 - 10000 * (output2 / 10000);
output2 /= 10000;
const uint32 c0 = (c % 100) << 1;
const uint32 c1 = (c / 100) << 1;
memcpy(result + index + olength - i - 1, DIGIT_TABLE + c0, 2);
memcpy(result + index + olength - i - 3, DIGIT_TABLE + c1, 2);
i += 4;
}
if (output2 >= 100)
{
const uint32 c = (output2 % 100) << 1;
output2 /= 100;
memcpy(result + index + olength - i - 1, DIGIT_TABLE + c, 2);
i += 2;
}
if (output2 >= 10)
{
const uint32 c = output2 << 1;
/*
* We can't use memcpy here: the decimal dot goes between these two
* digits.
*/
result[index + olength - i] = DIGIT_TABLE[c + 1];
result[index] = DIGIT_TABLE[c];
}
else
{
result[index] = (char) ('0' + output2);
}
/* Print decimal point if needed. */
if (olength > 1)
{
result[index + 1] = '.';
index += olength + 1;
}
else
{
++index;
}
/* Print the exponent. */
result[index++] = 'e';
if (exp < 0)
{
result[index++] = '-';
exp = -exp;
}
else
result[index++] = '+';
if (exp >= 100)
{
const int32 c = exp % 10;
memcpy(result + index, DIGIT_TABLE + 2 * (exp / 10), 2);
result[index + 2] = (char) ('0' + c);
index += 3;
}
else
{
memcpy(result + index, DIGIT_TABLE + 2 * exp, 2);
index += 2;
}
return index;
}
static inline bool
d2d_small_int(const uint64 ieeeMantissa,
const uint32 ieeeExponent,
floating_decimal_64 *v)
{
const int32 e2 = (int32) ieeeExponent - DOUBLE_BIAS - DOUBLE_MANTISSA_BITS;
/*
* Avoid using multiple "return false;" here since it tends to provoke the
* compiler into inlining multiple copies of d2d, which is undesirable.
*/
if (e2 >= -DOUBLE_MANTISSA_BITS && e2 <= 0)
{
/*----
* Since 2^52 <= m2 < 2^53 and 0 <= -e2 <= 52:
* 1 <= f = m2 / 2^-e2 < 2^53.
*
* Test if the lower -e2 bits of the significand are 0, i.e. whether
* the fraction is 0. We can use ieeeMantissa here, since the implied
* 1 bit can never be tested by this; the implied 1 can only be part
* of a fraction if e2 < -DOUBLE_MANTISSA_BITS which we already
* checked. (e.g. 0.5 gives ieeeMantissa == 0 and e2 == -53)
*/
const uint64 mask = (UINT64CONST(1) << -e2) - 1;
const uint64 fraction = ieeeMantissa & mask;
if (fraction == 0)
{
/*----
* f is an integer in the range [1, 2^53).
* Note: mantissa might contain trailing (decimal) 0's.
* Note: since 2^53 < 10^16, there is no need to adjust
* decimalLength().
*/
const uint64 m2 = (UINT64CONST(1) << DOUBLE_MANTISSA_BITS) | ieeeMantissa;
v->mantissa = m2 >> -e2;
v->exponent = 0;
return true;
}
}
return false;
}
/*
* Store the shortest decimal representation of the given double as an
* UNTERMINATED string in the caller's supplied buffer (which must be at least
* DOUBLE_SHORTEST_DECIMAL_LEN-1 bytes long).
*
* Returns the number of bytes stored.
*/
int
double_to_shortest_decimal_bufn(double f, char *result)
{
/*
* Step 1: Decode the floating-point number, and unify normalized and
* subnormal cases.
*/
const uint64 bits = double_to_bits(f);
/* Decode bits into sign, mantissa, and exponent. */
const bool ieeeSign = ((bits >> (DOUBLE_MANTISSA_BITS + DOUBLE_EXPONENT_BITS)) & 1) != 0;
const uint64 ieeeMantissa = bits & ((UINT64CONST(1) << DOUBLE_MANTISSA_BITS) - 1);
const uint32 ieeeExponent = (uint32) ((bits >> DOUBLE_MANTISSA_BITS) & ((1u << DOUBLE_EXPONENT_BITS) - 1));
/* Case distinction; exit early for the easy cases. */
if (ieeeExponent == ((1u << DOUBLE_EXPONENT_BITS) - 1u) || (ieeeExponent == 0 && ieeeMantissa == 0))
{
return copy_special_str(result, ieeeSign, (ieeeExponent != 0), (ieeeMantissa != 0));
}
floating_decimal_64 v;
const bool isSmallInt = d2d_small_int(ieeeMantissa, ieeeExponent, &v);
if (!isSmallInt)
{
v = d2d(ieeeMantissa, ieeeExponent);
}
return to_chars(v, ieeeSign, result);
}
/*
* Store the shortest decimal representation of the given double as a
* null-terminated string in the caller's supplied buffer (which must be at
* least DOUBLE_SHORTEST_DECIMAL_LEN bytes long).
*
* Returns the string length.
*/
int
double_to_shortest_decimal_buf(double f, char *result)
{
const int index = double_to_shortest_decimal_bufn(f, result);
/* Terminate the string. */
Assert(index < DOUBLE_SHORTEST_DECIMAL_LEN);
result[index] = '\0';
return index;
}
/*
* Return the shortest decimal representation as a null-terminated palloc'd
* string (outside the backend, uses malloc() instead).
*
* Caller is responsible for freeing the result.
*/
char *
double_to_shortest_decimal(double f)
{
char *const result = (char *) palloc(DOUBLE_SHORTEST_DECIMAL_LEN);
double_to_shortest_decimal_buf(f, result);
return result;
}
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