spark SparkFatalException 源码

  • 2022-10-20
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spark SparkFatalException 代码

文件路径:/core/src/main/scala/org/apache/spark/util/SparkFatalException.scala

/*
 * Licensed to the Apache Software Foundation (ASF) under one or more
 * contributor license agreements.  See the NOTICE file distributed with
 * this work for additional information regarding copyright ownership.
 * The ASF licenses this file to You under the Apache License, Version 2.0
 * (the "License"); you may not use this file except in compliance with
 * the License.  You may obtain a copy of the License at
 *
 *    http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */
package org.apache.spark.util

/**
 * SPARK-24294: To bypass scala bug: https://github.com/scala/bug/issues/9554, we catch
 * fatal throwable in {@link scala.concurrent.Future}'s body, and re-throw
 * SparkFatalException, which wraps the fatal throwable inside.
 * Note that SparkFatalException should only be thrown from a {@link scala.concurrent.Future},
 * which is run by using ThreadUtils.awaitResult. ThreadUtils.awaitResult will catch
 * it and re-throw the original exception/error.
 */
private[spark] final class SparkFatalException(val throwable: Throwable)
  extends Exception(throwable)

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